Explain how a car can be lifted by the hydraulic lift
1. Explain how a car can be lifted by the hydraulic lift
Answer:
Hydraulic lifts work on a basic principle: to go up, a pump pushes oil into the cylinder, pushing the piston (which pushes the lift car) up. To go down, the valve opens and oil is allowed to flow back into the reservoir, and is pushed back using the gravitational force of the lift car.
Explanation:
Hope It Helps!
Answer:
My name is jhon cena thats is my answer hope it helps
2. liquor van is lifted in tagalog
Explanation:
Hope it's help, Good luck!
Pa Brainliest pls
3. Jose owns a 1500-lb car and it needs to visit the mechanic. The car was lifted by a manually operated hydraulic lift, and the area of the shaft of the lift is 50cm^2; the area of the piston that forces liquid into the system is 4cm^2. What force must be exerted on this piston to lift the car?
Pascal's law was stated by a French philosopher and scientist, Blaise Pascal (1623-1662), saying:
“If external pressure is applied to a closed system, the pressure at any point in the fluid will increase proportion to the external pressure applied.”
Pascal's law describes that any increase in pressure on the surface of a fluid must be transmitted in all directions of the fluid. Pascal's law can only be applied to fluids, generally liquids.
Pascal's law in a closed system can be written as follows.
[tex]P_{1} = P_{2}[/tex]
As we already know that pressure is a force divided by the cross-sectional area (P = F/A), then the above equation can be rewritten as follows:
[tex]\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }[/tex]
Based on the questions above, the data are given:
Mass of the car (m) = 1,500 lb = 680.3886 kg (1 lb equal to 0.453592 kg)
The area of the piston for a lifted car ([tex]A_{1}[/tex]) = [tex]50 cm^{2}[/tex]
The area of the piston that forces liquid into the system ([tex]A_{2}[/tex]) = [tex]4 cm^{2}[/tex]
Solution:
Step 1: find the car’s weight.
[tex]F_{1} = m . g[/tex]
[tex]F_{1} = (680.3886) . (9.8)[/tex]
[tex]F_{1} = 6,667.80828 N[/tex]
Step 2: find the force that must be exerted on this piston to lift the car.
[tex]\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }[/tex]
[tex]\frac{6,667.80828}{50} = \frac{F_{2} }{4}[/tex]
[tex]F_{2} = \frac{(6,667.80828) . 4}{50}[/tex]
[tex]F_{2} = 533.425 N[/tex]
So, the force that must be exerted on this piston to lift 1,500 lb of Jose’s car is 533.425 N.
Learn more about hydraulic lifts: https://brainly.ph/question/10856765
#SPJ1
4. it is an example of a screw that lifts heavy cars? pasagot po please
Answer:
Jack screw or screw jack
Explanation:
sana po makatulong :)
5. why is it easier to lift your puppy than to try to lift your carPlss answer
Question:
why is it easier to lift your puppy than to try to lift your car
answer:
it's because your puppy is light (in weight)
and your car is made out of metal and steel
Answer:
Cause a puppy is light to carry. a car is so heavy like carrying 10 or more
printers
i hope it helped:)
6. ano sa Tagalog Ang lifting
Pagbubuhat
Yan lods
[tex]\huge\mathcal\blue{thanks}[/tex]
Answer:
pag bubuhat
Explanation:
basta pagbubuhat
7. A 1000 kg car is lifted to a height of 1.5 m. Solve for its potential energy.
Answer:
Therefore, the PE of the car is 14700J
Explanation:
To solve for potential energy of the car, we must use the formula below:
[tex] \boxed{\bold{PE = mgh}} [/tex]Wherein,
[tex] PE [/tex] - represents the Potential Energy[tex] m [/tex] - represents the mass[tex] g [/tex] - represents the gravitational force[tex] h [/tex] - represents the heightGiven from the problem:
[tex] m [/tex] = 1000lg[tex] g [/tex] = 9.8 m/s[tex] h [/tex] = 1.5mSubstitute the following givens to the problem
[tex] \rm{PE = (1000)(9.8)(1.5)=(9800)(1.5)=14700J} [/tex]Therefore, the PE of the car is 14700J
8. anuh s tagalog ang lifting
Answer:
Lifting means 'Buhatin'
Explanation:
'To lift something up; to raise something up; to carry something
'Upang iangat ang isang bagay; upang itaas ang isang bagay; upang dalhin ang isang bagay'
9. A crane lifts a 1500 kg car 20 m straight up. How much potential energy does the car gain?
The potential energy : 294 kJ
Further explanationEnergy can be interpreted as the ability to do work
There are several examples of energy
Potential energy is the energy that an object has because of the location of that object. Usually it is related to the force of gravity
PE = m . g . h
g = acceleration due to gravity ,(m/s²)
h = height , (m)
m = mass, (kg)
Given
mass = 1500 kg
height = 20 m
Solution
Input the value :
PE = 1500 kg x 9.8 m/s² x 20 m
PE = 294 kJ
Learn more
Potential Energy
https://brainly.ph/question/233160
https://brainly.ph/question/156465
the kinetic and potential energy
https://brainly.ph/question/250186
the formula of Potential Energy
https://brainly.ph/question/2212304
#LetsStudy
10. 1. How much potential energy does a car gain if a crane lifts the car with a massof 1,500 kg and 20 m straight up?
Calculating the Potential Energy.
Given
Mass (m) = 1500 kgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 20 mP.E = mgh
P.E = (1500)(9.8)(20)
P.E = 294000 J or 294 kJ
#CarryOnLearning
11. ano ang tagalog ng lift up
Answer: Buhatin
Explanation: Maari din ang itaas (mo)
12. Take car lifting and carrying
Answer:
nasan tanong mo?
Explanation:
tanong ko lang baka alam ko pero mahina ako English
Answer:
oh talaga sharmeyn? oh talaga sharmeynoh talaga sharmeyn?
oh talaga sharmeyn?oh talaga sharmeynoh talaga sharmeyn?
oh talaga sharmeyn?oh talaga sharmeynoh talaga sharmeyn?
oh talaga sharmeynoh talaga sharmeynoh talaga sharmeyn?
oh talaga sharmeynoh talaga sharmeynoh talaga sharmeyn?
oh talaga sharmeynoh talaga sharmeynoh talaga sharmey
13. A 1500kg car is placed on the large piston with a radius of 4m.a. What is the minimum upward force that the large piston must exert to lift the car?b. If the mechanical advantage of the hydraulic lift system is 20, What is the minimumdownward force that should be applied to lift the car?c. What is the radius of the small piston?d. What is the pressure exerted by the large piston?e. How far should the small piston descend in order to lift the car 2m?
Answer:
ok
Explanation:
ok
14. Two cars are lifted to the same elavation in a service station.If one car is twice as massive as the other, how do their potencial energies compare?
Answer:
If one car is twice as massive as the other, then the potential energies of the heavier car will be twice as much as the other car.
15. How will you compare the force needed to transport the car by lifting and by using an inclined plane?
Answer:
Moving an object up an inclined plane requires less force than lifting it straight up, at a cost of an increase in the distance moved. The mechanical advantage of an inclined plane, the factor by which the force is reduced, is equal to the ratio of the length of the sloped surface to the height it spans.
16. How much potential energy does a car gain if a crane lifts the car with a mass of 1500kg 20m up
Answer:
To calculate the potential energy gained by the car when lifted by the crane, we can use the formula:
PE = m * g * h
where PE is the potential energy gained, m is the mass of the car, g is the acceleration due to gravity, and h is the height that the car is lifted.
Substituting the given values, we get:
PE = 1500 kg * 9.81 m/s^2 * 20 m
= 294,300 J
Therefore, the potential energy gained by the car when lifted 20m up by the crane is 294,300 J.
#CARRYONLEARNINGAnswer:
29430 N
Explanation:
PE = mgh
PE = 1500kg(20m)(9.81m/s^2)
PE = 294.3 KN
17. what can hold a car but can't lift feather
A garage can hold a car but can't lift a feather.
Detailed answer:
A garage can hold a car but can't lift a feather because a garage is not at all designed to lift a feather.
There are other examples that are used in the same context.A garage is used for parking or holding cars.This is said so as we all know that a garage can never lift a feather as it does not have any parts that can lift a feather especially on its own.18. I'm sorry but I_________give you a lift because my car is broken
Answer:
Can't
Explanation:
#CarryOnLearning19. A car with a weight of 3000N is being lifted by a piston with an area of 3m^2, what is the weight needed to lift the car if the area of the piston is 0.8m^2. with solution...
Answer :
Solution :
Correct option is
A 2.67 x 10³n
Hydraulic lift works on the principle of pascal's law
P= F¹ = F¹
a¹ = a²
applying the given formula to the question.
1.2 x 10⁴ F
______ = ____
0.90 0.2
F= 0.24×10⁴
_________ =. 2.67×10³ N
0.90
20. 2. The car lifted its eyes of light. 3
Answer:
asan ang question
keep safe and healthy good day
21. ano sa tagalog ang shop-lift?
Answer:
Pag-angat ng tindahan
Explanation:
(correct me if I'm wrong)
22. what can hold a car but can't lift a feather
Answer:
air
Explanation:
i
23. They have pads that must be placed under the designated lift points of the car frame.
Answer:
Car has that pless brainliest
24. What is the GPE gained by the 500 kg car lifted 2m if the reference point of lifting was above the 7m? Show your solutions.
Answer:
35.71
Explanation:
500kg
7m
2m
500÷7
=71.42
71.42÷2
=35.71
25. I used for lifting the engine out or the car
Answer:
ENGINE CRANE
Explanation:
An engine crane (also referred as engine hoist) is a common repair tool used in vehicle repair shops to remove or install gasoline or diesel engines in small and crowded vehicle engine compartments.
26. what can hold a car but can't lift feather
Answer:
Garage
Explanation:
#Carryonlearning
#BrainlyCommunity
#BrainyEveryday
[tex] \large \color{lime} \mathtt{✨ TylerNyoPagodNa✨}[/tex]
27. ano po tagalog ng lifting diko po kasi alam patulong po
Answer:
Binubuhat nagbubuhat
28. The piston of a hydraulic automobile lift is 0.30 m in diameter. what gauge pressure, in pascals, is required to lift a car with a mass of 1200 kg? also express this pressure in atmospheres
GAUGE PRESSURE
The piston of a hydraulic automobile lift is 0.3 meters in diameter. The gauge pressure, in Pascal, need to lift a car with a mass of 1200 kilograms is 166.4 KPa or 1.64 atm
How did we get the answer?
We are going to use the formula where force is directly proportional to the product pressure and area.
F= PAFirst, let us calculate the pressure in Pascal.
P = [tex]\frac{1200(9.81)}{\frac{\pi}{4}(0.3)^2 }[/tex] = 166.4 KPa
Converting from Pa to atm:
Note: 1 atm is equal to 101,325 Pa
166.4 KPa x [tex]\frac{1 atm}{101,325Pa}[/tex] = 1.64 atm
If you would like to learn more about atmospheric pressure, kindly please take your time to visit and gain more knowledge on this link:https://brainly.ph/question/17526886
#SPJ4
29. A mechanic used a hydraulic lift to raise 12,054 N car 1.89 above the floor of a garage. It look 4.75 s to raise the car. What was the power output of the lift
Answer:
4796 Wattsi don't know if it is correct.
30. it is used for lifting the engine out og the car it is operated hydraulically by a hand pump
Answer:
hydraulic jack
Explanation:
hydraulic jack uses hydraulic power. The most common form is a car jack, floor jack or garage jack, which lifts vehicles so that maintenance can be performed. Jacks are usually rated for a maximum lifting capacity (for example, 1.5 tons or 3 tons).
sana po namkatulong
